Solar photovoltaic power station scheme design case

A solar power supply design example

Solar repeater power supply design

Repeater is one of the important means for the optimization of mobile communication networks. With the popularity of repeaters, the areas with good terrain, convenient power supply, and large users have basically covered, so in the process of network optimization, those terrains are complicated. If the power supply is difficult to use in places where cable power supply is continued, there will be hazards such as difficulty in line erection, high cost, inconvenient maintenance, and being prone to lightning strikes and other natural disasters. In order to enable the repeater station to better serve the network optimization, the solar energy powered repeater series provided by our company can better solve this problem.

First, the choice of repeater

As solar-powered repeater systems are often located in relatively high places, wireless repeaters are mainly used. According to the local signal conditions, it decides whether or not to adopt the frequency selection method. Taking into account the high ground and the capacity and cost of solar cells, the output power of the repeater should not exceed 20W.

Since the solar repeater is powered by solar energy into electrical energy, the energy consumption of the repeater is the key to the operating time of the repeater in adverse weather conditions. The most energy-consuming components of the repeater are In order to enable the power amplifier to achieve higher efficiency, our company uses a more efficient attack and release module to replace the original power amplifier. Although the cost has been increased, the efficiency of the equipment has been improved, and when no one is talking, The amplifier's operating current is only quiescent current.

Considering the aspect of networking, due to the limited energy supply from solar energy, the power consumption of the whole repeater station is not too large, and it is generally not more than 60w.

Second, the solar power system configuration

1, battery capacity

Assume that the power consumption of the repeater is 60w, and the current consumed by the repeater every day is (24V power supply):

2.5 x 24 hours = 60 (AH)

Set the battery capacity to meet the repeater's work for 15 days, then the minimum battery capacity is:

60×15=900(AH)

Although the nominal capacity of the battery is its rated discharge capacity, we only design it for 75% of the discharge capacity so that there is a certain amount of excess capacity. The total battery design capacity is:

900/0.75=1200(AH)

As for the combination of batteries, there are many ways such as:

12V×120AH×20

24V×120AH×10

2V×1200AH×12 etc.

According to the form of the engine room, the difficulty of transportation, other special requirements and other conditions to choose different ways.

2, the choice of solar panels

The charging current of a standard solar panel is 4A. In most solar panels in China, the maximum charging current of the solar panel is 3A, and the charging time at 3A is only 4 hours/day. The charging current at other times is Less than 3A. In cloudy days, the charging current of solar panels is only about 0.7A/piece, assuming that in the harsher weather, in 15 days, the sunny days are 4 days, the cloudy days are 6 days, and the rainy days are 5 days (without charging) every solar energy The output current of the board is:

On sunny days: 3A x 4 hours + (3A + 0.7) ÷ 2 x 4 hours = 19.4 (AH/day)

19.4 x 4 days = 77.6 (AH)

On cloudy days: 0.7A x 8 hours = 5.6 (AH/day)

5.6×6=33.6 (AH)

Total: 77.6+33.6=111.2(AH)

The use of 18 solar panels with an input voltage of 12V/4A will result in a total charge of 15 days:

18÷2×111.2=1008(AH)>900AH

It can meet the needs of the system power supply.

verification:

(1). Assuming that the weather is continuous rainy days and the solar panels cannot be charged, the system's continuous working time is:

900/60=15 days

(2). Assuming that the weather is continuous cloudy (or small sunny days), the working hours of the system are:

(900+5.6×9×T)/60=T

T=93.75 days

(3). Normal weather

From the previous calculations, it can be seen that the charge current in 15 days is 1008AH, which can fully meet the needs.

According to the actual situation, our company cooperates closely with solar cell manufacturers, according to the requirements of our company, develops and produces solar panels with 5% conversion efficiency, and can monitor the working conditions of solar cells through network management, such as charging current and charging. Voltage, battery operating voltage, etc.

3, repeater power selection

The above calculation is based on the power consumption of the repeater being 60 W (the output power is greater than 10 W). In the networking process, we can calculate the actual required output power of the repeater.

Set the required coverage distance to 3Km, (basic visibility) the path loss is:

LS=32.44+20lgf+20lgd

=32.44+20lg1000+20lg3

=102dB

Let the building loss be 20dB

The total attenuation is 122dB

Gain: Transmit power P

Antenna gain: 17dB

Antenna height correction factor 20lg50=34dB (position of repeater is generally higher)

The mobile phone receives indoor field strength of -85dBm.

Then -85=P+17+34-122

P=14dBm

Take P = 30dBm, you can fully meet the needs (16dB margin).

Even with a quad-frequency selective repeater, the output power of the repeater requires only 5W.

Therefore, according to the actual situation, in the situation that the repeater can meet the coverage, try to select a repeater with low power, one can save investment, and second, the working time of solar energy can be extended.

4, solar power configuration:

(1) Solar modules: 18 modules (40W/16.5V)

(2) Angle iron brackets: 2

(3) Solar Charger: 1

(4) Battery: 1200AH/24V

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